Itt mi történik miért lesz értelmetlen érték az obj2 tagváltozójába?

// main.cpp

# include <iostream>

class cProba {

public:

cProba(short proba = 0): i_proba(new short(proba)) {std::cout << "cProba konverzios-constructor \n";}

cProba(const cProba *const rhs): i_proba(new short(rhs->i_getProba())) {std::cout << "cProba copy constructor \n";}

~cProba() {delete i_proba; std::cout << "cProba destructor \n";}

const cProba *const operator=(const cProba *const);

short i_getProba()const {return *this->i_proba;}

operator short()const;

private:

short *i_proba; };

const cProba *const cProba::operator=(const cProba *const rhs) {

std::cout << "cProba operator=() \n";

if(this == rhs)

return this;

*this->i_proba = rhs->i_getProba();

return this; }

cProba::operator short()const {

std::cout << "cProba konverzios operator \n";

return (short(*i_proba)); }

int main() {

cProba obj1,obj2(4);

short k = 8;

std::cout << "\nobj1: "<< obj1.i_getProba() << std::endl

<< "obj2: "<< obj2.i_getProba() << std::endl << std::endl;

obj1 = obj2;

std::cout << "obj1: "<< obj1.i_getProba() << std::endl

<< "obj2: "<< obj2.i_getProba() << std::endl << std::endl;

obj2 = k;

std::cout << "obj1: "<< obj1.i_getProba() << std::endl

<< "obj2: "<< obj2.i_getProba() << std::endl << std::endl;

return 0; }